Difference between resistance and resistivity

resistance and resistivity difference and resistance and resistivity mastering physics
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Published Date:23-07-2017
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Electric Currents and Resistance II Physics 2415 Lecture 11 Michael Fowler, UVa Today’s Topics • First we’ll mention capacitors • Power usage: kWh, etc. • The microscopic picture • Temperature dependence of resistivity • Drift speed and electron speed • AC and DC • Semiconductors and superconductors Know This… • Capacitors in parallel (any number) are all at V V the same voltage V. • Capacitors in series (any number) all carry the • . same charge Q. -Q -Q Q Q • Putting these facts together with V = Q/C C 2 can solve a lot of C 1 problems Resistance and Resistivity • To summarize: for a given material (say, copper) the resistance of a piece of uniform wire is proportional to its length and inversely proportional to its cross-sectional area A. • This is written: R A  where is the resistivity. 8 1.6810 m. • For copper, Electric Power • Remember voltage is a measure of potential energy of electric charge, and if one coulomb drops through a potential difference of one volt it loses one joule of potential energy. • So a current of I amps flowing through a wire with V volts potential difference between the ends is losing IV joules per sec. • This energy appears as heat in the wire: the electric field accelerates the electrons, which then bump into impurities and defects in the wire, and are slowed down to begin accelerating again, like a sloping pinball machine. Power and Energy Usage • Using Ohm’s law, we can write the power use of a resistive heater (or equivalent device, such as a bulb) in different ways: 22 P IV I RV / R • The unit is watts, meaning joules per second. • Electric meters measure total energy usage: adding up how much power is drawn for how long, the standard unit is the kilowatt hour: • 1 kWh = 1,000x3,600J = 3.6MJ Microscopic Picture of Conductivity • The total current down the wire is I; if we assume it’s uniform over the cross section area A (which it is) there is a current 2 density j = I/A. (units: amps/m ) • A constant E field gives a steady current. This means the electrons are bouncing off things, like a sloping pinball machine, otherwise the current would keep accelerating. What are the Electrons Bouncing off? • Not the atoms It’s found experimentally that electrons pass dozens or often hundreds of atoms before being deflected. • Furthermore, an extremely pure crystal of copper has a very low resistance if it’s really cooled down….and the atoms are all still there. What are the Electrons Bouncing off? • Not the atoms • An extremely pure crystal of copper has a very low resistance if it’s really cooled down…. • This is the clue: they are deflected by thermal vibrations of the lattice—resistance increases with temperature. • The electrons also bounce off impurities, but can pass through a pure cold lattice like light through glass… electrons are really waves Temperature Dependence of Resistivity • Resistivity of metals increases approximately linearly with temperature over a wide range. • The formula is:  1TT  T00   being the resistance at some fixed T , and  the 0 0 temperature coefficient of resistivity. • An ordinary incandescent bulb has a tungsten wire at 15 about 3300K, and  = 0.0045, from which T 0 not so far off proportional to absolute temperature. Clicker Question • What is the resistance of a 12V, 36 Watt headlight bulb? A. 3 ohms B. 4 ohms C. 0.3 ohms Clicker Answer • What is the resistance of a 12V, 36 Watt headlight bulb? A. 3 ohms B. 4 ohms C. 0.3 ohms • Power of 36W = IV, V = 12 so I = 3. Then I = V/R. Clicker Question • Assume the 12V, 36 Watt headlight bulb has a tungsten filament. What is its approximate power output in the first instant it is connected, 15 cold, to the 12V battery? ( ). T 0 A. 36W B. 2.4W C. 540W Clicker Answer • Assume the 12V, 36 Watt headlight bulb has a tungsten filament. What is its approximate power output in the first instant it is connected, 15 cold, to the 12V battery? ( ). T 0 A. 36W B. 2.4W C. 540W 2 Power P = IV = V /R: R when initially cold is 1/15 of R at operating temperature of 3300K. Drift Speed • Take a piece of copper wire, say 1mmx1mm cross section, 1m long carrying 5 amps. 23 • This is 1cc of Cu, about 10 gms, about 10 conduction electrons (one per atom), about 15,000C of electron charge. • Therefore, at 5 amps (C/sec) it takes 3000secs for an electron to drift 1m. -4 • Bottom line: the drift velocity is of order 10 m/sec. (it’s linear in current, and depends on wire thickness for given current, obviously.) Drift Speed and Electron Speed • Take a piece of copper wire, say 1mmx1mm cross section, 1m long carrying 5 amps: this wire has resistance RA  /  0.0 2 so from E 0.1 V/m Ohm’s law . • This field will accelerate the electrons, ma = eE, 10 2 approximate accn = 2x10 m/s . This reaches -14 drift velocity in about 0.5x10 seconds, that must be time between collisions. • Electron speed (from quantum mechanics) is 6 -8 about 2x10 m/s, so goes of order 10 m between collisions—past dozens of atoms. AC and DC • Batteries provide direct current, DC: it always flows in the same direction. • Almost all electric generators produce a voltage of sine wave form: V V sin 2 ft V sin t 00 • This drives an alternating current, AC, Vt sin 0 I I sint 0 R and power 2 2 2 2 2 PVI I R I Rsin t V / R sin t  00AC Average Power and rms Values 22 • The AC power P  V / R s in  t varies  0 rapidly ( = 2f, f = 60 Hz here), what is significant for most uses is the average power. 2 average value of sint 2 • The average value of sint is ½. must equal average value 2 of cost. and remember 2 2 2 sint + cost = 1 V V V/2 • Define V by rms rms 0 2 • Then the average power PV / R rms The standard 120V AC power is V = 120V. rms So the maximum voltage V on a 120V line is 120x2 = 170V 0Why Bother with AC? • Because, as we’ll discuss a little later, it’s very easy to transform from high voltage to low voltage using transformers. • This means very high voltages can be used for longer distance transmission, low voltages for local use. Clicker Question • The resistivity of aluminum is 58% higher than that of copper. • A copper high voltage line has diameter 1 cm. If is replaced by an aluminum line of the same resistance, the aluminum line has diameter: A. 1.58cm B. 1.27cm C. 0.8 cm D. O.64 cm